Login

Concepts

Read through concept notes with worked explanations and diagrams, chapter by chapter.

Concept 01 / 06Some Basic Concepts of Chemistry

Laws of Chemical Combination and Dalton's Atomic Theory

Conservation of mass, definite proportions, multiple proportions, reciprocal proportions, Gay-Lussac's law of gaseous volumes and Avogadro's law, how Dalton's atomic theory explains them, and the modern exceptions such as isotopes and non-stoichiometric compounds.

Figure 1
Chemistry became quantitative when a handful of experimental laws about the masses and volumes of reacting substances were discovered. Each law is a direct consequence of matter being made of atoms that combine in whole-number ratios. Law of conservation of mass (Lavoisier). In a chemical reaction the total mass of the reactants equals the total mass of the products. Atoms are rearranged, not created or destroyed. (In nuclear reactions mass and energy interconvert through E=mc2E = mc^{2}; in chemical reactions the mass change corresponding to reaction energies is far too small to measure.) Law of definite proportions (Proust). A given compound always contains the same elements combined in the same fixed ratio by mass, whatever its source. Pure water always contains hydrogen and oxygen in the mass ratio 1:81 : 8. Exceptions: compounds made with different isotopes (for example H2O\mathrm{H_{2}O} and D2O\mathrm{D_{2}O} differ in mass ratio), and non-stoichiometric solids such as Fe0.95O\mathrm{Fe_{0.95}O}, whose composition varies because of crystal defects. Law of multiple proportions (Dalton). If two elements form more than one compound, the masses of one element that combine with a fixed mass of the other are in a simple whole-number ratio. With 1212 g of carbon, oxygen combines as 1616 g in CO\mathrm{CO} and 3232 g in CO2\mathrm{CO_{2}}, a ratio of 1:21 : 2, as in the figure. This law is the strongest evidence for atoms: a whole-number ratio of masses reflects a whole-number ratio of atoms. Law of reciprocal proportions (Richter). If elements AA and BB each combine with a fixed mass of CC, then the ratio in which AA and BB combine with each other is the same as, or a simple multiple of, the ratio of those masses. This led to the idea of equivalent masses. Gay-Lussac's law of gaseous volumes. At the same temperature and pressure, the volumes of reacting gases and gaseous products are in simple whole-number ratios. For example, 22 volumes of hydrogen react with 11 volume of oxygen to give 22 volumes of steam. Avogadro's law. Equal volumes of all gases at the same temperature and pressure contain equal numbers of molecules. It explains Gay-Lussac's law, and it forced the idea that elementary gases such as hydrogen and oxygen exist as diatomic molecules: 2H2+O2→2H2O2\mathrm{H_{2}} + \mathrm{O_{2}} \rightarrow 2\mathrm{H_{2}O} gives 22 volumes of steam, which would be impossible if oxygen were monatomic. Dalton's atomic theory. Matter consists of indivisible atoms; atoms of an element are identical in mass and properties; atoms of different elements differ; compounds form when atoms combine in simple whole-number ratios; reactions rearrange atoms. Modern corrections: atoms are divisible (electrons, protons, neutrons), and atoms of one element can differ in mass (isotopes). The theory still correctly explains all the mass laws above. Key Takeaways: - Mass is conserved in chemical reactions. - Definite proportions: fixed mass ratio for a compound (exceptions: isotopes, non-stoichiometric solids). - Multiple proportions: masses of one element per fixed mass of the other are in whole-number ratio. - Gay-Lussac: gas volumes react in simple ratios at the same TT and PP. - Avogadro: equal volumes contain equal numbers of molecules; elementary gases like H2\mathrm{H_{2}}, O2\mathrm{O_{2}}, N2\mathrm{N_{2}} are diatomic. - Pitfall: applying Gay-Lussac's volume ratios to liquids or solids. Brain-Teaser 1: Two oxides of a metal contain 27.6%27.6\% and 30.0%30.0\% oxygen by mass. Show that they obey the law of multiple proportions. Solution: Per 100100 g of oxide: first oxide has 72.472.4 g metal and 27.627.6 g O, so O per gram of metal =27.672.4=0.381= \frac{27.6}{72.4} = 0.381. Second: 70.070.0 g metal and 30.030.0 g O, so 30.070.0=0.4286\frac{30.0}{70.0} = 0.4286. Ratio 0.3810.4286=0.889≈89\frac{0.381}{0.4286} = 0.889 \approx \frac{8}{9}. A simple whole-number ratio (8:98 : 9) confirms the law; these are the data for Fe3O4\mathrm{Fe_{3}O_{4}} and Fe2O3\mathrm{Fe_{2}O_{3}} (oxygen per iron 43:32=8:9\frac{4}{3} : \frac{3}{2} = 8 : 9). The trick is always to fix the mass of one element before comparing. Brain-Teaser 2: 1010 mL of a gaseous hydrocarbon needs 3030 mL of oxygen for complete combustion and gives 2020 mL of CO2\mathrm{CO_{2}}, all at the same TT and PP. Find the formula. Solution: By Avogadro's law, volumes are proportional to moles. CxHy+(x+y4)O2→xCO2+y2H2O\mathrm{C_{x}H_{y}} + (x + \frac{y}{4})\mathrm{O_{2}} \rightarrow x\mathrm{CO_{2}} + \frac{y}{2}\mathrm{H_{2}O}. Per mL of hydrocarbon: x=2x = 2 and x+y4=3x + \frac{y}{4} = 3, so y=4y = 4. The gas is C2H4\mathrm{C_{2}H_{4}} (ethene). Volume data translate directly into mole ratios for gases. Brain-Teaser 3: When 1.001.00 g of magnesium is burnt in a sealed flask containing excess oxygen, the flask's mass is unchanged. When burnt in an open crucible, the crucible gains mass. Explain both observations. Solution: In the sealed flask, the oxygen consumed was already inside, so the total mass of the closed system is conserved. In the open crucible, oxygen from the air (not originally weighed) combines with the magnesium: 2Mg+O2→2MgO2\mathrm{Mg} + \mathrm{O_{2}} \rightarrow 2\mathrm{MgO}, so the solid gains the mass of that oxygen (about 0.660.66 g, giving 1.661.66 g of MgO\mathrm{MgO}). Conservation of mass applies to the whole system, including gases entering or leaving, which is the usual source of apparent violations.