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Concept 03 / 06Coordination Compounds

Isomerism in Coordination Compounds

Structural isomerism (ionisation, solvate or hydrate, linkage and coordination isomerism) and stereoisomerism: geometrical (cis-trans in square planar and octahedral complexes, fac-mer) and optical isomerism in octahedral chelate complexes, with counting of isomers.

Figure 1
Isomers have the same formula but different arrangements of atoms. Structural isomerism. Ionisation isomerism: a counter ion itself could be a ligand and exchanges with a ligand, giving different ions in solution: [Co(NH3)5(SO4)]Br\mathrm{[Co(NH_{3})_{5}(SO_{4})]Br} (gives AgBr) and [Co(NH3)5Br]SO4\mathrm{[Co(NH_{3})_{5}Br]SO_{4}} (gives BaSO4\mathrm{BaSO_{4}}). Solvate (hydrate) isomerism: water is inside or outside the coordination sphere: [Cr(H2O)6]Cl3\mathrm{[Cr(H_{2}O)_{6}]Cl_{3}} (violet), [Cr(H2O)5Cl]Cl2⋅H2O\mathrm{[Cr(H_{2}O)_{5}Cl]Cl_{2} \cdot H_{2}O} (grey-green), [Cr(H2O)4Cl2]Cl⋅2H2O\mathrm{[Cr(H_{2}O)_{4}Cl_{2}]Cl \cdot 2H_{2}O} (dark green). Linkage isomerism: an ambidentate ligand binds through different atoms: [Co(NH3)5(NO2)]Cl2\mathrm{[Co(NH_{3})_{5}(NO_{2})]Cl_{2}} (nitrito-N, yellow) and [Co(NH3)5(ONO)]Cl2\mathrm{[Co(NH_{3})_{5}(ONO)]Cl_{2}} (nitrito-O, red). Coordination isomerism: exchange of ligands between cationic and anionic complexes: [Co(NH3)6][Cr(CN)6]\mathrm{[Co(NH_{3})_{6}][Cr(CN)_{6}]} and [Cr(NH3)6][Co(CN)6]\mathrm{[Cr(NH_{3})_{6}][Co(CN)_{6}]}. Geometrical isomerism (see figure). Arises in heteroleptic complexes because ligands can occupy different relative positions. Square planar [MA2B2]\mathrm{[MA_{2}B_{2}]} (such as [Pt(NH3)2Cl2]\mathrm{[Pt(NH_{3})_{2}Cl_{2}]}): cis (like ligands adjacent) and trans (opposite). Also [MABXL]\mathrm{[MABXL]} gives three isomers. Tetrahedral complexes do not show geometrical isomerism (all positions are adjacent). Octahedral [MA4B2]\mathrm{[MA_{4}B_{2}]} (such as [Co(NH3)4Cl2]+\mathrm{[Co(NH_{3})_{4}Cl_{2}]^{+}}): cis and trans. [M(AA)2B2]\mathrm{[M(AA)_{2}B_{2}]} (such as [CoCl2(en)2]+\mathrm{[CoCl_{2}(en)_{2}]^{+}}): cis and trans. Octahedral [MA3B3]\mathrm{[MA_{3}B_{3}]} (such as [Co(NH3)3(NO2)3]\mathrm{[Co(NH_{3})_{3}(NO_{2})_{3}]}): facial (fac: the three A on one triangular face) and meridional (mer: the three A in a plane containing the metal, around the meridian). Optical isomerism. Complexes that are non-superimposable on their mirror images (chiral) exist as d and l enantiomers. Common in octahedral complexes with didentate ligands: [M(AA)3]\mathrm{[M(AA)_{3}]} (such as [Co(en)3]3+\mathrm{[Co(en)_{3}]^{3+}}): a pair of enantiomers. cis-[M(AA)2B2]\mathrm{[M(AA)_{2}B_{2}]} (such as cis-[PtCl2(en)2]2+\mathrm{[PtCl_{2}(en)_{2}]^{2+}}): optically active; the trans isomer has a plane of symmetry and is inactive. So [CoCl2(en)2]+\mathrm{[CoCl_{2}(en)_{2}]^{+}} has three stereoisomers in total. Square planar complexes are rarely optically active (the plane is a symmetry plane). Key Takeaways: - Structural: ionisation, hydrate, linkage (ambidentate), coordination. - [MA2B2]\mathrm{[MA_{2}B_{2}]} square planar and [MA4B2]\mathrm{[MA_{4}B_{2}]} octahedral: cis/trans. - [MA3B3]\mathrm{[MA_{3}B_{3}]}: fac/mer. - [M(AA)3]\mathrm{[M(AA)_{3}]} and cis-[M(AA)2B2]\mathrm{[M(AA)_{2}B_{2}]} are optically active. - Pitfall: tetrahedral [MA2B2]\mathrm{[MA_{2}B_{2}]} shows no geometrical isomerism. Brain-Teaser 1: How many isomers (including stereoisomers) does [CoCl2(en)2]+\mathrm{[CoCl_{2}(en)_{2}]^{+}} have? Solution: Geometrical: cis and trans. The trans isomer is achiral; the cis isomer is chiral and exists as d and l forms. Total 33. Brain-Teaser 2: Identify the type of isomerism: (a) [Co(NH3)5(NO2)]2+\mathrm{[Co(NH_{3})_{5}(NO_{2})]^{2+}} and [Co(NH3)5(ONO)]2+\mathrm{[Co(NH_{3})_{5}(ONO)]^{2+}}; (b) [Pt(NH3)4][PtCl4]\mathrm{[Pt(NH_{3})_{4}][PtCl_{4}]} and [Pt(NH3)3Cl][Pt(NH3)Cl3]\mathrm{[Pt(NH_{3})_{3}Cl][Pt(NH_{3})Cl_{3}]}; (c) [Co(NH3)5Br]SO4\mathrm{[Co(NH_{3})_{5}Br]SO_{4}} and [Co(NH3)5SO4]Br\mathrm{[Co(NH_{3})_{5}SO_{4}]Br}. Solution: (a) linkage; (b) coordination; (c) ionisation. Brain-Teaser 3: Why does [Pt(NH3)2Cl2]\mathrm{[Pt(NH_{3})_{2}Cl_{2}]} show geometrical isomerism but [Zn(NH3)2Cl2]\mathrm{[Zn(NH_{3})_{2}Cl_{2}]} does not? Solution: Pt2+\mathrm{Pt^{2+}} (d8d^{8}) forms a square planar complex, in which two positions can be adjacent (cis) or opposite (trans). Zn2+\mathrm{Zn^{2+}} (d10d^{10}) forms a tetrahedral complex, where every pair of positions is adjacent, so only one arrangement exists.

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