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Concept 04 / 06The d and f Block Elements
Important Compounds: Potassium Dichromate and Potassium Permanganate
Preparation of potassium dichromate from chromite ore, chromate-dichromate equilibrium and structures, oxidising reactions of acidified dichromate; preparation of potassium permanganate from pyrolusite (fusion, disproportionation or electrolytic oxidation), its structure and colour, and oxidising reactions in acidic, neutral and alkaline media.
Figure 1
Potassium dichromate, K2Cr2O7.
Preparation from chromite ore (FeCr2O4):
1. Fusion with sodium carbonate in free air: 4FeCr2O4+8Na2CO3+7O2→8Na2CrO4+2Fe2O3+8CO2.
2. The yellow sodium chromate solution is filtered and acidified with H2SO4: 2Na2CrO4+2H+→Na2Cr2O7+2Na++H2O (orange).
3. Treatment with KCl gives the less soluble potassium salt: Na2Cr2O7+2KCl→K2Cr2O7+2NaCl.
Chromate-dichromate equilibrium (see figure): 2CrO42−+2H+⇌Cr2O72−+H2O. In acid, orange dichromate dominates; in alkali, yellow chromate. Chromium is +6 in both (not a redox reaction). Chromate is tetrahedral; dichromate consists of two tetrahedra sharing one corner oxygen (Cr-O-Cr angle 126∘).
Oxidising action (acidic solution): Cr2O72−+14H++6e−→2Cr3++7H2O, E∘=1.33V (orange to green).
6I−→3I2; 6Fe2+→6Fe3+; 3H2S→3S; 3Sn2+→3Sn4+; for example Cr2O72−+3H2S+8H+→2Cr3++3S+7H2O.
Uses: primary standard in volumetric analysis (it is not hygroscopic), leather tanning, oxidant in organic chemistry, chrome alum.
Potassium permanganate, KMnO4.
Preparation: pyrolusite (MnO2) is fused with KOH and an oxidant (air or KNO3) to give dark green potassium manganate: 2MnO2+4KOH+O2→2K2MnO4+2H2O. Manganate disproportionates in neutral or acidic solution: 3MnO42−+4H+→2MnO4−+MnO2+2H2O. Commercially, it is oxidised electrolytically in alkaline solution: MnO42−→MnO4−+e−. In the laboratory, Mn2+ is oxidised by peroxodisulfate: 2Mn2++5S2O82−+8H2O→2MnO4−+10SO42−+16H+.
Structure and properties: permanganate is tetrahedral with Mn in +7 (d0, diamagnetic); its intense purple colour is due to charge transfer; manganate (Mn6+, d1) is green and paramagnetic. On heating to 513K: 2KMnO4→K2MnO4+MnO2+O2.
Oxidising action:
acidic (MnO4−+8H++5e−→Mn2++4H2O, E∘=1.52V): I−→I2, Fe2+→Fe3+, C2O42−→CO2 (at 333K), H2S→S, SO32−→SO42−, NO2−→NO3−;
neutral or faintly alkaline (MnO4−+2H2O+3e−→MnO2+4OH−): I−→IO3−, S2O32−→SO42−, Mn2+→MnO2 (in presence of zinc sulfate or zinc oxide).
Uses: oxidant in analysis (self-indicator), bleaching of wool, cotton and silk, disinfectant, decolourisation of oils.
Key Takeaways:
- Chromite + Na2CO3/air → Na2CrO4 → (acid) Na2Cr2O7 → (KCl) K2Cr2O7.
- Chromate (yellow, alkali) ⇌ dichromate (orange, acid); both Cr +6.
- Cr2O72−: 6 electrons, orange to green Cr3+.
- MnO2 → K2MnO4 (green) → KMnO4 (purple) by disproportionation or electrolytic oxidation.
- In neutral medium, permanganate gives MnO2 and oxidises iodide to iodate.
- Pitfall: the chromate-dichromate interconversion changes colour but is not a redox reaction.
Brain-Teaser 1: How many moles of K2Cr2O7 are needed to oxidise 3mol of H2S in acid, and what is the colour change?
Solution: Cr2O72−+3H2S+8H+→2Cr3++3S+7H2O: 1mol dichromate for 3molH2S (each S loses 2 electrons; dichromate gains 6). The solution turns from orange to green, with a pale yellow precipitate of sulfur.
Brain-Teaser 2: Why is KMnO4 purple although manganese is in the +7 (d0) state?
Solution: With no d electrons, d-d transitions are impossible. The colour arises from ligand-to-metal charge transfer: an electron from an oxygen p orbital is excited into an empty Mn d orbital by absorption of green-yellow light, so the transmitted light appears purple.
Brain-Teaser 3: What happens when potassium manganate is dissolved in dilute acid? Write the equation and identify the type of reaction.
Solution: Green manganate disproportionates: 3MnO42−+4H+→2MnO4−+MnO2+2H2O. Mn(+6) is both oxidised to +7 (purple permanganate) and reduced to +4 (brown MnO2 precipitate).