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Concept 04 / 09The p-Block Elements

Group 14 Elements: Trends, Catenation and Allotropes of Carbon

General characteristics of carbon, silicon, germanium, tin and lead: oxidation states and inert pair effect, catenation and multiple bonding, anomalous carbon, and the structures and properties of diamond, graphite, fullerenes and other forms of carbon.

Figure 1
Group 14: carbon and silicon (non-metals), germanium (metalloid), tin and lead (metals). Configuration ns2np2ns^{2}np^{2}. Trends. Atomic radius increases down the group (with only a small increase from Si to Ge and from Sn to Pb, because of poorly shielding d and f electrons). Ionisation enthalpies are higher than group 13 and generally decrease down the group. Electronegativity is fairly constant from Si to Pb (about 1.81.8 to 1.91.9). Oxidation states. +4+4 and +2+2. The inert pair effect makes +2+2 more stable down the group: Ge2+\mathrm{Ge^{2+}} is a reducing agent (tends to +4+4), Sn2+\mathrm{Sn^{2+}} is a reducing agent, while Pb4+\mathrm{Pb^{4+}} is a strong oxidising agent (PbO2\mathrm{PbO_{2}}) and Pb2+\mathrm{Pb^{2+}} is the stable state. In the +4+4 state, the group forms mainly covalent compounds; Si and heavier elements can expand their covalency beyond 44 using d orbitals (SiF62−\mathrm{SiF_{6}^{2-}}, [SnCl6]2−\mathrm{[SnCl_{6}]^{2-}}), but carbon cannot. Hence CCl4\mathrm{CCl_{4}} is not hydrolysed, while SiCl4\mathrm{SiCl_{4}} is: SiCl4+4H2O→Si(OH)4+4HCl\mathrm{SiCl_{4} + 4H_{2}O \rightarrow Si(OH)_{4} + 4HCl} (water attacks the vacant d orbital of Si). Catenation. The ability to form chains and rings with itself. It depends on the strength of the E-E bond: C-C 348348, Si-Si 297297, Ge-Ge 260260, Sn-Sn 240 kJ mol−1240\,\mathrm{kJ\,mol^{-1}}. Carbon catenates far more than any other element, the basis of organic chemistry; lead shows none. Anomalous carbon. Small size, high electronegativity, no d orbitals: maximum covalency 44; forms strong pπp\pi-pπp\pi multiple bonds with itself and with O and N (C=C\mathrm{C=C}, C≡N\mathrm{C \equiv N}, C=O\mathrm{C=O}); heavier members do not, so CO2\mathrm{CO_{2}} is a gas of discrete molecules while SiO2\mathrm{SiO_{2}} is a network solid. Allotropes of carbon (see figure). Diamond: each C is sp3sp^{3} and tetrahedrally bonded to four others (C-C 154 pm154\,\mathrm{pm}) in a rigid 3D network. Hardest natural substance, very high melting point, electrical insulator (no free electrons), excellent heat conductor. Used in cutting tools and jewellery. Graphite: layers of sp2sp^{2} carbon in hexagonal rings (C-C 141.5 pm141.5\,\mathrm{pm}), with one delocalised π\pi electron per atom; layers held by weak van der Waals forces, 340 pm340\,\mathrm{pm} apart. Soft and slippery (lubricant), good electrical conductor along the layers. Graphite is the thermodynamically most stable form (ΔfH∘\Delta_{f}H^{\circ} of diamond is +1.9 kJ mol−1+1.9\,\mathrm{kJ\,mol^{-1}}); diamond is made from graphite at very high pressure and temperature. Fullerenes: discovered in 1985; C60\mathrm{C_{60}} (buckminsterfullerene) is a soccer-ball molecule of 1212 five-membered and 2020 six-membered rings, all sp2sp^{2} carbon. It is the only pure molecular form of carbon, soluble in organic solvents. Other forms: graphene (a single graphite layer), carbon nanotubes, and microcrystalline forms such as coke, charcoal and carbon black (impure graphite). Key Takeaways: - Stability of +2+2 increases down the group: Pb2+\mathrm{Pb^{2+}} stable, PbO2\mathrm{PbO_{2}} oxidant, SnCl2\mathrm{SnCl_{2}} reductant. - Catenation: C >> Si > Ge ≈ Sn; follows E-E bond strength. - CCl4\mathrm{CCl_{4}} does not hydrolyse (no d orbitals); SiCl4\mathrm{SiCl_{4}} does. - Diamond sp3sp^{3} insulator; graphite sp2sp^{2} conductor; C60\mathrm{C_{60}} has 1212 pentagons and 2020 hexagons. - Pitfall: graphite, not diamond, is the standard state of carbon. Brain-Teaser 1: Why is PbO2\mathrm{PbO_{2}} a strong oxidising agent while SnO2\mathrm{SnO_{2}} is not? Solution: The inert pair effect makes +2+2 the stable state for lead, so Pb4+\mathrm{Pb^{4+}} readily gains two electrons (as in PbO2+4HCl→PbCl2+Cl2+2H2O\mathrm{PbO_{2} + 4HCl \rightarrow PbCl_{2} + Cl_{2} + 2H_{2}O}). For tin, +4+4 is the more stable state, so SnO2\mathrm{SnO_{2}} has little tendency to be reduced. Brain-Teaser 2: Graphite conducts electricity but diamond does not. Explain from hybridisation. Solution: In diamond, all four valence electrons of each carbon are used in localised sp3sp^{3} σ\sigma bonds, leaving no mobile electrons. In graphite, each sp2sp^{2} carbon uses three electrons in σ\sigma bonds; the fourth occupies a p orbital perpendicular to the layer, and these overlap into a delocalised π\pi system that allows electrons to move along the layers. Brain-Teaser 3: How many carbon-carbon single and double bonds are in one Kekule structure of C60\mathrm{C_{60}}? Solution: Each carbon has three neighbours, so the number of C-C bonds =60×32=90= \frac{60 \times 3}{2} = 90. Each carbon has one double bond, so there are 602=30\frac{60}{2} = 30 double bonds and 90−30=6090 - 30 = 60 single bonds.