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Concept 08 / 08Equilibrium

Solubility Product, Common Ion Effect and Precipitation

Solubility equilibria of sparingly soluble salts, the solubility product Ksp and its relation to molar solubility for different stoichiometries, comparing solubilities, the common ion effect, the ionic product condition for precipitation, and selective precipitation in qualitative analysis.

Figure 1
Solubility equilibrium. A saturated solution of a sparingly soluble ionic salt is in equilibrium with the undissolved solid: AxBy(s)⇌xAy+(aq)+yBx−(aq)\mathrm{A_{x}B_{y}(s) \rightleftharpoons xA^{y+}(aq) + yB^{x-}(aq)}. Since the solid is omitted, the equilibrium constant is the solubility product Ksp=[Ay+]x[Bx−]yK_{sp} = [\mathrm{A^{y+}}]^{x}[\mathrm{B^{x-}}]^{y}, which depends only on temperature. Relation to molar solubility ss (in mol L−1\mathrm{mol\,L^{-1}}, in pure water): AB\mathrm{AB} (AgCl\mathrm{AgCl}, BaSO4\mathrm{BaSO_{4}}): Ksp=s2K_{sp} = s^{2}. AB2\mathrm{AB_{2}} or A2B\mathrm{A_{2}B} (CaF2\mathrm{CaF_{2}}, Ag2CrO4\mathrm{Ag_{2}CrO_{4}}): Ksp=4s3K_{sp} = 4s^{3}. AB3\mathrm{AB_{3}} (Fe(OH)3\mathrm{Fe(OH)_{3}}): Ksp=27s4K_{sp} = 27s^{4}. A3B2\mathrm{A_{3}B_{2}} (Ca3(PO4)2\mathrm{Ca_{3}(PO_{4})_{2}}): Ksp=108s5K_{sp} = 108s^{5}. In general, Ksp=xxyysx+yK_{sp} = x^{x}y^{y}s^{x + y}. Solubilities can be compared directly from KspK_{sp} only for salts of the same type. Common ion effect. Solubility decreases in a solution that already contains one of the ions. For AgCl in c Mc\,\mathrm{M} NaCl: s(s+c)=Ksps(s + c) = K_{sp}, so s≈Kspcs \approx \frac{K_{sp}}{c} when c≫sc \gg s (see figure). This is why excess precipitating reagent is used in gravimetric analysis and why NaCl is purified by passing HCl gas into its saturated solution. (Very high concentrations can raise solubility again through complex formation, such as AgCl2−\mathrm{AgCl_{2}^{-}}.) Precipitation condition. Compare the ionic product QspQ_{sp} (same expression as KspK_{sp} with actual concentrations after mixing) with KspK_{sp}: Qsp>KspQ_{sp} > K_{sp}: supersaturated, precipitation occurs. Qsp=KspQ_{sp} = K_{sp}: saturated. Qsp<KspQ_{sp} < K_{sp}: unsaturated, no precipitate; more solid can dissolve. Remember that mixing dilutes each solution. Selective precipitation. In qualitative analysis, group II sulfides (CuS\mathrm{CuS}, PbS\mathrm{PbS}, CdS\mathrm{CdS}; tiny KspK_{sp}) are precipitated with H2S\mathrm{H_{2}S} in acidic medium, where H+\mathrm{H^{+}} suppresses [S2−]\mathrm{[S^{2-}]} (common ion effect), so only they exceed their KspK_{sp}. Group IV sulfides (ZnS\mathrm{ZnS}, NiS\mathrm{NiS}, CoS\mathrm{CoS}, MnS\mathrm{MnS}; larger KspK_{sp}) need the higher [S2−]\mathrm{[S^{2-}]} of ammoniacal medium. Similarly, group III hydroxides (Fe(OH)3\mathrm{Fe(OH)_{3}}, Al(OH)3\mathrm{Al(OH)_{3}}) are precipitated by NH4OH\mathrm{NH_{4}OH} in the presence of NH4Cl\mathrm{NH_{4}Cl}, which lowers [OH−]\mathrm{[OH^{-}]} enough to keep Mg(OH)2\mathrm{Mg(OH)_{2}} and group IV hydroxides in solution. Key Takeaways: - Ksp=xxyysx+yK_{sp} = x^{x}y^{y}s^{x + y}; s2s^{2}, 4s34s^{3}, 27s427s^{4}, 108s5108s^{5}. - Common ion: s≈Kspcs \approx \frac{K_{sp}}{c} for a 1:1 salt. - Precipitation when Qsp>KspQ_{sp} > K_{sp}. - Compare solubilities through ss, not KspK_{sp}, for salts of different types. - Pitfall: after mixing equal volumes, each concentration halves. Brain-Teaser 1: KspK_{sp} of AgCl is 1.8×10−101.8 \times 10^{-10} and of Ag2CrO4\mathrm{Ag_{2}CrO_{4}} is 1.1×10−121.1 \times 10^{-12}. Which is more soluble in water? Solution: AgCl: s=1.8×10−10=1.34×10−5 Ms = \sqrt{1.8 \times 10^{-10}} = 1.34 \times 10^{-5}\,\mathrm{M}. Ag2CrO4\mathrm{Ag_{2}CrO_{4}}: s=(1.1×10−124)1/3=6.5×10−5 Ms = \left(\frac{1.1 \times 10^{-12}}{4}\right)^{1/3} = 6.5 \times 10^{-5}\,\mathrm{M}. Silver chromate is about five times more soluble, despite its smaller KspK_{sp}. (This is why, in Mohr's titration, AgCl precipitates before red Ag2CrO4\mathrm{Ag_{2}CrO_{4}} appears at the end point.) Brain-Teaser 2: Equal volumes of 2×10−4 M2 \times 10^{-4}\,\mathrm{M} AgNO3\mathrm{AgNO_{3}} and 2×10−4 M2 \times 10^{-4}\,\mathrm{M} NaCl are mixed. Will AgCl precipitate? Solution: After mixing, [Ag+]=[Cl−]=10−4 M[\mathrm{Ag^{+}}] = [\mathrm{Cl^{-}}] = 10^{-4}\,\mathrm{M}. Qsp=10−8>1.8×10−10Q_{sp} = 10^{-8} > 1.8 \times 10^{-10}, so a precipitate forms. Brain-Teaser 3: The solubility of Mg(OH)2\mathrm{Mg(OH)_{2}} in water is 1.4×10−4 M1.4 \times 10^{-4}\,\mathrm{M}. Find its KspK_{sp} and its solubility in a solution of pH 1212. Solution: Ksp=4s3=4×(1.4×10−4)3=1.1×10−11K_{sp} = 4s^{3} = 4 \times (1.4 \times 10^{-4})^{3} = 1.1 \times 10^{-11}. At pH 1212, [OH−]=10−2[\mathrm{OH^{-}}] = 10^{-2}, so s=Ksp[OH−]2=1.1×10−1110−4=1.1×10−7 Ms = \frac{K_{sp}}{[\mathrm{OH^{-}}]^{2}} = \frac{1.1 \times 10^{-11}}{10^{-4}} = 1.1 \times 10^{-7}\,\mathrm{M}, over a thousand times less.